-(6b-4)-7(b-4)=28

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Solution for -(6b-4)-7(b-4)=28 equation: 



-(6b-4)-7(b-4)=28

We move all terms to the left:

-(6b-4)-7(b-4)-(28)=0

We multiply parentheses

-(6b-4)-7b+28-28=0

We get rid of parentheses

-6b-7b+4+28-28=0

We add all the numbers together, and all the variables

-13b+4=0

We move all terms containing b to the left, all other terms to the right

-13b=-4

b=-4/-13

b=4/13

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