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3(4x-15)=5(2x-5)
We move all terms to the left:
3(4x-15)-(5(2x-5))=0
We multiply parentheses
12x-(5(2x-5))-45=0
We calculate terms in parentheses: -(5(2x-5)), so:We get rid of parentheses
5(2x-5)
We multiply parentheses
10x-25
Back to the equation:
-(10x-25)
12x-10x+25-45=0
We add all the numbers together, and all the variables
2x-20=0
We move all terms containing x to the left, all other terms to the right
2x=20
x=20/2
x=10
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