-(4b+2)=2(b-1)

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Solution for -(4b+2)=2(b-1) equation: 



-(4b+2)=2(b-1)

We move all terms to the left:

-(4b+2)-(2(b-1))=0

We get rid of parentheses

-4b-(2(b-1))-2=0



We calculate terms in parentheses: -(2(b-1)), so:

2(b-1)

We multiply parentheses

2b-2

Back to the equation:

-(2b-2)



We get rid of parentheses

-4b-2b+2-2=0

We add all the numbers together, and all the variables

-6b=0

b=0/-6

b=0

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