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1/3(9-6h)=h+21
We move all terms to the left:
1/3(9-6h)-(h+21)=0
Domain of the equation: 3(9-6h)!=0We add all the numbers together, and all the variables
h∈R
1/3(-6h+9)-(h+21)=0
We get rid of parentheses
1/3(-6h+9)-h-21=0
We multiply all the terms by the denominator
-h*3(-6h+9)-21*3(-6h+9)+1=0
Wy multiply elements
-3h^2(--63h(-+1=0
We use the square of the difference formula
-3h^2(+63h(-1=0
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