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11x=21/2x+12
We move all terms to the left:
11x-(21/2x+12)=0
Domain of the equation: 2x+12)!=0We get rid of parentheses
x∈R
11x-21/2x-12=0
We multiply all the terms by the denominator
11x*2x-12*2x-21=0
Wy multiply elements
22x^2-24x-21=0
a = 22; b = -24; c = -21;
Δ = b2-4ac
Δ = -242-4·22·(-21)
Δ = 2424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2424}=\sqrt{4*606}=\sqrt{4}*\sqrt{606}=2\sqrt{606}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-2\sqrt{606}}{2*22}=\frac{24-2\sqrt{606}}{44} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+2\sqrt{606}}{2*22}=\frac{24+2\sqrt{606}}{44} $
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