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-(2x-4)-(8x-6)+13=-5(x-1)-(10x+5)+3
We move all terms to the left:
-(2x-4)-(8x-6)+13-(-5(x-1)-(10x+5)+3)=0
We get rid of parentheses
-2x-8x-(-5(x-1)-(10x+5)+3)+4+6+13=0
We calculate terms in parentheses: -(-5(x-1)-(10x+5)+3), so:We add all the numbers together, and all the variables
-5(x-1)-(10x+5)+3
We multiply parentheses
-5x-(10x+5)+5+3
We get rid of parentheses
-5x-10x-5+5+3
We add all the numbers together, and all the variables
-15x+3
Back to the equation:
-(-15x+3)
-10x-(-15x+3)+23=0
We get rid of parentheses
-10x+15x-3+23=0
We add all the numbers together, and all the variables
5x+20=0
We move all terms containing x to the left, all other terms to the right
5x=-20
x=-20/5
x=-4
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