X=2,8x(1-x)

Solution for X=2,8x(1-x) equation:

X=2.8X(1-X)

We move all terms to the left:

X-(2.8X(1-X))=0

We add all the numbers together, and all the variables

X-(2.8X(-1X+1))=0


We calculate terms in parentheses: -(2.8X(-1X+1)), so:

2.8X(-1X+1)

We multiply parentheses

-2X^2+2X

Back to the equation:

-(-2X^2+2X)


We get rid of parentheses

2X^2-2X+X=0

We add all the numbers together, and all the variables

2X^2-1X=0

a = 2; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·2·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*2}=\frac{0}{4}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*2}=\frac{2}{4}
=1/2
$