(X+3)*(x+9)=952

Solution for (X+3)*(x+9)=952 equation:

(X+3)(X+9)=952

We move all terms to the left:

(X+3)(X+9)-(952)=0

We multiply parentheses ..

(+X^2+9X+3X+27)-952=0

We get rid of parentheses

X^2+9X+3X+27-952=0

We add all the numbers together, and all the variables

X^2+12X-925=0

a = 1; b = 12; c = -925;
Δ = b2-4ac
Δ = 122-4·1·(-925)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-62}{2*1}=\frac{-74}{2}
=-37
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+62}{2*1}=\frac{50}{2}
=25
$