(z-6)/(2z+1)=10

Solution for (z-6)/(2z+1)=10 equation:

(z-6)/(2z+1)=10

We move all terms to the left:

(z-6)/(2z+1)-(10)=0


Domain of the equation: (2z+1)!=0

We move all terms containing z to the left, all other terms to the right

2z!=-1

z!=-1/2

z!=-1/2

z∈R


We multiply all the terms by the denominator


(z-6)-10*(2z+1)=0

We multiply parentheses

(z-6)-20z-10=0

We get rid of parentheses

z-20z-6-10=0

We add all the numbers together, and all the variables

-19z-16=0

We move all terms containing z to the left, all other terms to the right

-19z=16

z=16/-19

z=-16/19