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23=5x+2-x2
We move all terms to the left:
23-(5x+2-x2)=0
We add all the numbers together, and all the variables
-(+5x-1x^2+2)+23=0
We get rid of parentheses
1x^2-5x-2+23=0
We add all the numbers together, and all the variables
x^2-5x+21=0
a = 1; b = -5; c = +21;
Δ = b2-4ac
Δ = -52-4·1·21
Δ = -59
Delta is less than zero, so there is no solution for the equation
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