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(5x-32)(x-8)=180
We move all terms to the left:
(5x-32)(x-8)-(180)=0
We multiply parentheses ..
(+5x^2-40x-32x+256)-180=0
We get rid of parentheses
5x^2-40x-32x+256-180=0
We add all the numbers together, and all the variables
5x^2-72x+76=0
a = 5; b = -72; c = +76;
Δ = b2-4ac
Δ = -722-4·5·76
Δ = 3664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3664}=\sqrt{16*229}=\sqrt{16}*\sqrt{229}=4\sqrt{229}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-4\sqrt{229}}{2*5}=\frac{72-4\sqrt{229}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+4\sqrt{229}}{2*5}=\frac{72+4\sqrt{229}}{10} $
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