(z-27)+(z-41)=(z+10)

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Solution for (z-27)+(z-41)=(z+10) equation: 



(z-27)+(z-41)=(z+10)

We move all terms to the left:

(z-27)+(z-41)-((z+10))=0

We get rid of parentheses

z+z-((z+10))-27-41=0



We calculate terms in parentheses: -((z+10)), so:

(z+10)

We get rid of parentheses

z+10

Back to the equation:

-(z+10)



We add all the numbers together, and all the variables

2z-(z+10)-68=0

We get rid of parentheses

2z-z-10-68=0

We add all the numbers together, and all the variables

z-78=0

We move all terms containing z to the left, all other terms to the right

z=78

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