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6b+6=-1+5(b-3)
We move all terms to the left:
6b+6-(-1+5(b-3))=0
We calculate terms in parentheses: -(-1+5(b-3)), so:We get rid of parentheses
-1+5(b-3)
determiningTheFunctionDomain 5(b-3)-1
We multiply parentheses
5b-15-1
We add all the numbers together, and all the variables
5b-16
Back to the equation:
-(5b-16)
6b-5b+16+6=0
We add all the numbers together, and all the variables
b+22=0
We move all terms containing b to the left, all other terms to the right
b=-22
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