(y-8)/3=(y+4)/2

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Solution for (y-8)/3=(y+4)/2 equation: 



(y-8)/3=(y+4)/2

We move all terms to the left:

(y-8)/3-((y+4)/2)=0

We calculate fractions


y/()+(-((y+4)*3)/()=0



We calculate terms in parentheses: +(-((y+4)*3)/(), so:

-((y+4)*3)/(

We multiply all the terms by the denominator


-((y+4)*3)



We calculate terms in parentheses: -((y+4)*3), so:

(y+4)*3

We multiply parentheses

3y+12

Back to the equation:

-(3y+12)



We get rid of parentheses

-3y-12

Back to the equation:

+(-3y-12)



We get rid of parentheses

y/()-3y-12=0

We multiply all the terms by the denominator


y-3y*()-12*()=0

We add all the numbers together, and all the variables

y-3y*()=0

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