6x-4(3x+3)=5(2x-3)+5

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Solution for 6x-4(3x+3)=5(2x-3)+5 equation: 



6x-4(3x+3)=5(2x-3)+5

We move all terms to the left:

6x-4(3x+3)-(5(2x-3)+5)=0

We multiply parentheses

6x-12x-(5(2x-3)+5)-12=0



We calculate terms in parentheses: -(5(2x-3)+5), so:

5(2x-3)+5

We multiply parentheses

10x-15+5

We add all the numbers together, and all the variables

10x-10

Back to the equation:

-(10x-10)



We add all the numbers together, and all the variables

-6x-(10x-10)-12=0

We get rid of parentheses

-6x-10x+10-12=0

We add all the numbers together, and all the variables

-16x-2=0

We move all terms containing x to the left, all other terms to the right

-16x=2

x=2/-16

x=-1/8

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