(X+2)/5=5-(x+3)/2

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Solution for (X+2)/5=5-(x+3)/2 equation: 



(X+2)/5=5-(X+3)/2

We move all terms to the left:

(X+2)/5-(5-(X+3)/2)=0

We calculate fractions


X/()+(-(5-(X+3)*5)/()=0



We calculate terms in parentheses: +(-(5-(X+3)*5)/(), so:

-(5-(X+3)*5)/(

We multiply all the terms by the denominator


-(5-(X+3)*5)



We calculate terms in parentheses: -(5-(X+3)*5), so:

5-(X+3)*5

determiningTheFunctionDomain
-(X+3)*5+5

We multiply parentheses

-5X-15+5

We add all the numbers together, and all the variables

-5X-10

Back to the equation:

-(-5X-10)



We get rid of parentheses

5X+10

Back to the equation:

+(5X+10)



We get rid of parentheses

X/()+5X+10=0

We multiply all the terms by the denominator


X+5X*()+10*()=0

We add all the numbers together, and all the variables

X+5X*()=0

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