(y)^2+2y+2=0

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Solution for (y)^2+2y+2=0 equation: 



(y)^2+2y+2=0

a = 1; b = 2; c = +2;
Δ = b2-4ac
Δ = 22-4·1·2
Δ = -4
Delta is less than zero, so there is no solution for the equation

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