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(x/7)+(3x/4)=7(1/7)
We move all terms to the left:
(x/7)+(3x/4)-(7(1/7))=0
We add all the numbers together, and all the variables
(+x/7)+(+3x/4)-(7(+1/7))=0
We get rid of parentheses
x/7+3x/4-(7(+1/7))=0
We calculate fractions
1029x^2/()+4x/()+()/()=0
We add all the numbers together, and all the variables
1029x^2/()+4x/()+1=0
We multiply all the terms by the denominator
1029x^2+4x+1*()=0
We add all the numbers together, and all the variables
1029x^2+4x=0
a = 1029; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·1029·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*1029}=\frac{-8}{2058} =-4/1029 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*1029}=\frac{0}{2058} =0 $
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