If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(9x-8)(4x+3)=0
We multiply parentheses ..
(+36x^2+27x-32x-24)=0
We get rid of parentheses
36x^2+27x-32x-24=0
We add all the numbers together, and all the variables
36x^2-5x-24=0
a = 36; b = -5; c = -24;
Δ = b2-4ac
Δ = -52-4·36·(-24)
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3481}=59$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-59}{2*36}=\frac{-54}{72} =-3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+59}{2*36}=\frac{64}{72} =8/9 $
| 20+x3=27 | | 42+15+.25x=45+.35x | | x9=153 | | y9=153 | | 253=-5(6v-5) | | 14x+26=90 | | x2+10=11 | | 2s+18=16-4(s+7) | | (x+6/5)=13 | | a^2+16=100 | | 3(c+2)=-5-2(c-3) | | 7(x+1)-5x=4+2x+3 | | 16+b^2=100 | | 5(m+2)-6+3m=3(3m+3)-m | | 5x-28=3x+20 | | -4d+11=-53 | | y+2.5=5.43 | | {z-1}{3}=6 | | 1/4χ²-x-15=0 | | 10-(4-4n)+18n=-6+18(n+1) | | 2x-8+8x=12 | | 3.4p-4.2+2.9p=-3.2+5.3p | | 2x+x=5x-x | | 7x+23=5x+19 | | 0=-(x)^3+2(x)^2 | | 5y-9-3y+8=0 | | 5y-9-3y+8=9 | | 13=12n-3 | | (3x/4)+(x/3)=13/4 | | 6x-5=6(x-6) | | (3x/4)+(x/3)=(13/4) | | 3x/4+x/3=13/4 |