(3x/4)+(x/3)=(13/4)

Solution for (3x/4)+(x/3)=(13/4) equation:

(3x/4)+(x/3)=(13/4)

We move all terms to the left:

(3x/4)+(x/3)-((13/4))=0

We add all the numbers together, and all the variables

(+3x/4)+(+x/3)-((+13/4))=0

We get rid of parentheses

3x/4+x/3-((+13/4))=0

We calculate fractions


64x^2/()+9x/()+()/()=0

We add all the numbers together, and all the variables

64x^2/()+9x/()+1=0

We multiply all the terms by the denominator


64x^2+9x+1*()=0

We add all the numbers together, and all the variables

64x^2+9x=0

a = 64; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·64·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*64}=\frac{-18}{128}
=-9/64
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*64}=\frac{0}{128}
=0
$