3(c+2)=-5-2(c-3)

Solution for 3(c+2)=-5-2(c-3) equation:

3(c+2)=-5-2(c-3)

We move all terms to the left:

3(c+2)-(-5-2(c-3))=0

We multiply parentheses

3c-(-5-2(c-3))+6=0


We calculate terms in parentheses: -(-5-2(c-3)), so:

-5-2(c-3)

determiningTheFunctionDomain
-2(c-3)-5

We multiply parentheses

-2c+6-5

We add all the numbers together, and all the variables

-2c+1

Back to the equation:

-(-2c+1)


We get rid of parentheses

3c+2c-1+6=0

We add all the numbers together, and all the variables

5c+5=0

We move all terms containing c to the left, all other terms to the right

5c=-5

c=-5/5

c=-1