(x/5)-(2X/3)=(9/7)-(x)

Solution for (x/5)-(2X/3)=(9/7)-(x) equation:

(x/5)-(2x/3)=(9/7)-(x)

We move all terms to the left:

(x/5)-(2x/3)-((9/7)-(x))=0


Domain of the equation: 7)-x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+x/5)-(+2x/3)-((+9/7)-x)=0

We get rid of parentheses

x/5-2x/3-((+9/7)-x)=0

We calculate fractions


(-490x^2)/735x+147x^2/735x+()/735x=0

We multiply all the terms by the denominator


(-490x^2)+147x^2+()=0

We add all the numbers together, and all the variables

147x^2+(-490x^2)=0

We get rid of parentheses

147x^2-490x^2=0

We add all the numbers together, and all the variables

-343x^2=0

a = -343; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-343)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-686}=0$