F(x)=4x2-2x

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Solution for F(x)=4x2-2x equation:



(F)=4F^2-2F
We move all terms to the left:
(F)-(4F^2-2F)=0
We get rid of parentheses
-4F^2+F+2F=0
We add all the numbers together, and all the variables
-4F^2+3F=0
a = -4; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-4)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-4}=\frac{-6}{-8} =3/4 $
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-4}=\frac{0}{-8} =0 $

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