2(x+1)+3(x-2)=4(2x-x)+6

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Solution for 2(x+1)+3(x-2)=4(2x-x)+6 equation: 



2(x+1)+3(x-2)=4(2x-x)+6

We move all terms to the left:

2(x+1)+3(x-2)-(4(2x-x)+6)=0

We add all the numbers together, and all the variables

2(x+1)+3(x-2)-(4(+x)+6)=0

We multiply parentheses

2x+3x-(4(+x)+6)+2-6=0



We calculate terms in parentheses: -(4(+x)+6), so:

4(+x)+6

We multiply parentheses

4x+6

Back to the equation:

-(4x+6)



We add all the numbers together, and all the variables

5x-(4x+6)-4=0

We get rid of parentheses

5x-4x-6-4=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10

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