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(x-5)+3x+12=7x-56
We move all terms to the left:
(x-5)+3x+12-(7x-56)=0
We add all the numbers together, and all the variables
3x+(x-5)-(7x-56)+12=0
We get rid of parentheses
3x+x-7x-5+56+12=0
We add all the numbers together, and all the variables
-3x+63=0
We move all terms containing x to the left, all other terms to the right
-3x=-63
x=-63/-3
x=+21
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