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3x-1/4x=56
We move all terms to the left:
3x-1/4x-(56)=0
Domain of the equation: 4x!=0We multiply all the terms by the denominator
x!=0/4
x!=0
x∈R
3x*4x-56*4x-1=0
Wy multiply elements
12x^2-224x-1=0
a = 12; b = -224; c = -1;
Δ = b2-4ac
Δ = -2242-4·12·(-1)
Δ = 50224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{50224}=\sqrt{16*3139}=\sqrt{16}*\sqrt{3139}=4\sqrt{3139}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-224)-4\sqrt{3139}}{2*12}=\frac{224-4\sqrt{3139}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-224)+4\sqrt{3139}}{2*12}=\frac{224+4\sqrt{3139}}{24} $
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