If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x=75/2.7x
We move all terms to the left:
x-(75/2.7x)=0
Domain of the equation: 2.7x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(+75/2.7x)=0
We get rid of parentheses
x-75/2.7x=0
We multiply all the terms by the denominator
x*2.7x-75=0
Wy multiply elements
2x^2-75=0
a = 2; b = 0; c = -75;
Δ = b2-4ac
Δ = 02-4·2·(-75)
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{6}}{2*2}=\frac{0-10\sqrt{6}}{4} =-\frac{10\sqrt{6}}{4} =-\frac{5\sqrt{6}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{6}}{2*2}=\frac{0+10\sqrt{6}}{4} =\frac{10\sqrt{6}}{4} =\frac{5\sqrt{6}}{2} $
| 9x-3=68 | | 2c=70 | | (x)(x)(9)=68 | | 3+x=4.5 | | (k-4)^2=169 | | (k-4)2=169 | | (5x-6)=(7x+12 | | 3(4x+1)=4(9+3x) | | V=x(8-2x)(6-2x) | | 24=3/2y=36 | | x^2-2^x+19=0 | | X^2-34x+81=0 | | V(a)=(8-2a)(6a-2a) | | x=74/2.7*x | | 4x+3+2x+3=90 | | 5x+7/2=3x-14 | | -8+20x=22x-66 | | (x-3)3x2+4x+3=(x-3)x2+x-5 | | x=7+12.3 | | 6(2-x)=36 | | C=40+9x | | x=3+12.3 | | 7(2(3x-6)=3(x+2) | | 2x-3²=10x | | x³-x+12/x=11 | | 12-6x=6(4(2x)+6 | | X³-X+12/x=0 | | 4x+1•4=42 | | 5(2x-9)-5=5(x-3)-25 | | 8-x/7=-7 | | 12y-4=15y-9 | | 3x-12+4x=6x(6 |