(x-3)/4=(x-5)/2

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Solution for (x-3)/4=(x-5)/2 equation: 



(x-3)/4=(x-5)/2

We move all terms to the left:

(x-3)/4-((x-5)/2)=0

We calculate fractions


x/()+(-((x-5)*4)/()=0



We calculate terms in parentheses: +(-((x-5)*4)/(), so:

-((x-5)*4)/(

We multiply all the terms by the denominator


-((x-5)*4)



We calculate terms in parentheses: -((x-5)*4), so:

(x-5)*4

We multiply parentheses

4x-20

Back to the equation:

-(4x-20)



We get rid of parentheses

-4x+20

Back to the equation:

+(-4x+20)



We get rid of parentheses

x/()-4x+20=0

We multiply all the terms by the denominator


x-4x*()+20*()=0

We add all the numbers together, and all the variables

x-4x*()=0

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