(x-3)/2=(2x-5)/3

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Solution for (x-3)/2=(2x-5)/3 equation: 



(x-3)/2=(2x-5)/3

We move all terms to the left:

(x-3)/2-((2x-5)/3)=0

We calculate fractions


x/()+(-((2x-5)*2)/()=0



We calculate terms in parentheses: +(-((2x-5)*2)/(), so:

-((2x-5)*2)/(

We multiply all the terms by the denominator


-((2x-5)*2)



We calculate terms in parentheses: -((2x-5)*2), so:

(2x-5)*2

We multiply parentheses

4x-10

Back to the equation:

-(4x-10)



We get rid of parentheses

-4x+10

Back to the equation:

+(-4x+10)



We get rid of parentheses

x/()-4x+10=0

We multiply all the terms by the denominator


x-4x*()+10*()=0

We add all the numbers together, and all the variables

x-4x*()=0

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