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3(x+1)(x+1)=30
We move all terms to the left:
3(x+1)(x+1)-(30)=0
We multiply parentheses ..
3(+x^2+x+x+1)-30=0
We multiply parentheses
3x^2+3x+3x+3-30=0
We add all the numbers together, and all the variables
3x^2+6x-27=0
a = 3; b = 6; c = -27;
Δ = b2-4ac
Δ = 62-4·3·(-27)
Δ = 360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{360}=\sqrt{36*10}=\sqrt{36}*\sqrt{10}=6\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{10}}{2*3}=\frac{-6-6\sqrt{10}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{10}}{2*3}=\frac{-6+6\sqrt{10}}{6} $
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