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2(2x+1)=3-(x-1)
We move all terms to the left:
2(2x+1)-(3-(x-1))=0
We multiply parentheses
4x-(3-(x-1))+2=0
We calculate terms in parentheses: -(3-(x-1)), so:We get rid of parentheses
3-(x-1)
determiningTheFunctionDomain -(x-1)+3
We get rid of parentheses
-x+1+3
We add all the numbers together, and all the variables
-1x+4
Back to the equation:
-(-1x+4)
4x+1x-4+2=0
We add all the numbers together, and all the variables
5x-2=0
We move all terms containing x to the left, all other terms to the right
5x=2
x=2/5
x=2/5
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