(x-3)*(x-4)=1056

Solution for (x-3)*(x-4)=1056 equation:

(x-3)(x-4)=1056

We move all terms to the left:

(x-3)(x-4)-(1056)=0

We multiply parentheses ..

(+x^2-4x-3x+12)-1056=0

We get rid of parentheses

x^2-4x-3x+12-1056=0

We add all the numbers together, and all the variables

x^2-7x-1044=0

a = 1; b = -7; c = -1044;
Δ = b2-4ac
Δ = -72-4·1·(-1044)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4225}=65$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-65}{2*1}=\frac{-58}{2}
=-29
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+65}{2*1}=\frac{72}{2}
=36
$