(x+5)(x+2)-3(4x-3)=(x+5)(x+5)

Solution for (x+5)(x+2)-3(4x-3)=(x+5)(x+5) equation:

(x+5)(x+2)-3(4x-3)=(x+5)(x+5)

We move all terms to the left:

(x+5)(x+2)-3(4x-3)-((x+5)(x+5))=0

We multiply parentheses

(x+5)(x+2)-12x-((x+5)(x+5))+9=0

We multiply parentheses ..

(+x^2+2x+5x+10)-12x-((x+5)(x+5))+9=0


We calculate terms in parentheses: -((x+5)(x+5)), so:

(x+5)(x+5)

We multiply parentheses ..

(+x^2+5x+5x+25)

We get rid of parentheses

x^2+5x+5x+25

We add all the numbers together, and all the variables

x^2+10x+25

Back to the equation:

-(x^2+10x+25)


We get rid of parentheses

x^2-x^2+2x+5x-12x-10x+10-25+9=0

We add all the numbers together, and all the variables

-15x-6=0

We move all terms containing x to the left, all other terms to the right

-15x=6

x=6/-15

x=-2/5