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(x-20)(x-20)=1000
We move all terms to the left:
(x-20)(x-20)-(1000)=0
We multiply parentheses ..
(+x^2-20x-20x+400)-1000=0
We get rid of parentheses
x^2-20x-20x+400-1000=0
We add all the numbers together, and all the variables
x^2-40x-600=0
a = 1; b = -40; c = -600;
Δ = b2-4ac
Δ = -402-4·1·(-600)
Δ = 4000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4000}=\sqrt{400*10}=\sqrt{400}*\sqrt{10}=20\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-20\sqrt{10}}{2*1}=\frac{40-20\sqrt{10}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+20\sqrt{10}}{2*1}=\frac{40+20\sqrt{10}}{2} $
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