(12x+28)=(10x+20)

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Solution for (12x+28)=(10x+20) equation: 



(12x+28)=(10x+20)

We move all terms to the left:

(12x+28)-((10x+20))=0

We get rid of parentheses

12x-((10x+20))+28=0



We calculate terms in parentheses: -((10x+20)), so:

(10x+20)

We get rid of parentheses

10x+20

Back to the equation:

-(10x+20)



We get rid of parentheses

12x-10x-20+28=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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