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2-3(1-2x)=5-2(2x+3)
We move all terms to the left:
2-3(1-2x)-(5-2(2x+3))=0
We add all the numbers together, and all the variables
-3(-2x+1)-(5-2(2x+3))+2=0
We multiply parentheses
6x-(5-2(2x+3))-3+2=0
We calculate terms in parentheses: -(5-2(2x+3)), so:We add all the numbers together, and all the variables
5-2(2x+3)
determiningTheFunctionDomain -2(2x+3)+5
We multiply parentheses
-4x-6+5
We add all the numbers together, and all the variables
-4x-1
Back to the equation:
-(-4x-1)
6x-(-4x-1)-1=0
We get rid of parentheses
6x+4x+1-1=0
We add all the numbers together, and all the variables
10x=0
x=0/10
x=0
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