(x-2)(x+3)-(x-5)(x+4)=-5-(x-1)

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Solution for (x-2)(x+3)-(x-5)(x+4)=-5-(x-1) equation: 



(x-2)(x+3)-(x-5)(x+4)=-5-(x-1)

We move all terms to the left:

(x-2)(x+3)-(x-5)(x+4)-(-5-(x-1))=0

We multiply parentheses ..

(+x^2+3x-2x-6)-(x-5)(x+4)-(-5-(x-1))=0



We calculate terms in parentheses: -(-5-(x-1)), so:

-5-(x-1)

determiningTheFunctionDomain
-(x-1)-5

We get rid of parentheses

-x+1-5

We add all the numbers together, and all the variables

-1x-4

Back to the equation:

-(-1x-4)



We get rid of parentheses

x^2+3x-2x-(x-5)(x+4)+1x-6+4=0

We multiply parentheses ..

x^2-(+x^2+4x-5x-20)+3x-2x+1x-6+4=0

We add all the numbers together, and all the variables

x^2-(+x^2+4x-5x-20)+2x-2=0

We get rid of parentheses

x^2-x^2-4x+5x+2x+20-2=0

We add all the numbers together, and all the variables

3x+18=0

We move all terms containing x to the left, all other terms to the right

3x=-18

x=-18/3

x=-6

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