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10(3n+1)(8n-3)=0
We multiply parentheses ..
10(+24n^2-9n+8n-3)=0
We multiply parentheses
240n^2-90n+80n-30=0
We add all the numbers together, and all the variables
240n^2-10n-30=0
a = 240; b = -10; c = -30;
Δ = b2-4ac
Δ = -102-4·240·(-30)
Δ = 28900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{28900}=170$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-170}{2*240}=\frac{-160}{480} =-1/3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+170}{2*240}=\frac{180}{480} =3/8 $
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