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1x=8/1x
We move all terms to the left:
1x-(8/1x)=0
Domain of the equation: 1x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1x-(+8/1x)=0
We add all the numbers together, and all the variables
x-(+8/1x)=0
We get rid of parentheses
x-8/1x=0
We multiply all the terms by the denominator
x*1x-8=0
Wy multiply elements
x^2-8=0
a = 1; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·1·(-8)
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{2}}{2*1}=\frac{0-4\sqrt{2}}{2} =-\frac{4\sqrt{2}}{2} =-2\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{2}}{2*1}=\frac{0+4\sqrt{2}}{2} =\frac{4\sqrt{2}}{2} =2\sqrt{2} $
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