(x-1)(x-3)=(x+2)(x-5)

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Solution for (x-1)(x-3)=(x+2)(x-5) equation: 



(x-1)(x-3)=(x+2)(x-5)

We move all terms to the left:

(x-1)(x-3)-((x+2)(x-5))=0

We multiply parentheses ..

(+x^2-3x-1x+3)-((x+2)(x-5))=0



We calculate terms in parentheses: -((x+2)(x-5)), so:

(x+2)(x-5)

We multiply parentheses ..

(+x^2-5x+2x-10)

We get rid of parentheses

x^2-5x+2x-10

We add all the numbers together, and all the variables

x^2-3x-10

Back to the equation:

-(x^2-3x-10)



We get rid of parentheses

x^2-x^2-3x-1x+3x+3+10=0

We add all the numbers together, and all the variables

-1x+13=0

We move all terms containing x to the left, all other terms to the right

-x=-13

x=-13/-1

x=+13

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