15=3(y-1)+2(4-y)

Solution for 15=3(y-1)+2(4-y) equation:

15=3(y-1)+2(4-y)

We move all terms to the left:

15-(3(y-1)+2(4-y))=0

We add all the numbers together, and all the variables

-(3(y-1)+2(-1y+4))+15=0


We calculate terms in parentheses: -(3(y-1)+2(-1y+4)), so:

3(y-1)+2(-1y+4)

We multiply parentheses

3y-2y-3+8

We add all the numbers together, and all the variables

y+5

Back to the equation:

-(y+5)


We get rid of parentheses

-y-5+15=0

We add all the numbers together, and all the variables

-1y+10=0

We move all terms containing y to the left, all other terms to the right

-y=-10

y=-10/-1

y=+10