0=3(1-2v)-5(2-v)

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Solution for 0=3(1-2v)-5(2-v) equation: 



0=3(1-2v)-5(2-v)

We move all terms to the left:

0-(3(1-2v)-5(2-v))=0

We add all the numbers together, and all the variables

-(3(-2v+1)-5(-1v+2))+0=0

We add all the numbers together, and all the variables

-(3(-2v+1)-5(-1v+2))=0



We calculate terms in parentheses: -(3(-2v+1)-5(-1v+2)), so:

3(-2v+1)-5(-1v+2)

We multiply parentheses

-6v+5v+3-10

We add all the numbers together, and all the variables

-1v-7

Back to the equation:

-(-1v-7)



We get rid of parentheses

1v+7=0

We add all the numbers together, and all the variables

v+7=0

We move all terms containing v to the left, all other terms to the right

v=-7

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