(x+7)/3-(3x-7)/2=(x-1)/2

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Solution for (x+7)/3-(3x-7)/2=(x-1)/2 equation: 



(x+7)/3-(3x-7)/2=(x-1)/2

We move all terms to the left:

(x+7)/3-(3x-7)/2-((x-1)/2)=0

We calculate fractions


x/()+(-9x+21)/()+(-((x-1)*3)/()=0



We calculate terms in parentheses: +(-((x-1)*3)/(), so:

-((x-1)*3)/(

We multiply all the terms by the denominator


-((x-1)*3)



We calculate terms in parentheses: -((x-1)*3), so:

(x-1)*3

We multiply parentheses

3x-3

Back to the equation:

-(3x-3)



We get rid of parentheses

-3x+3

Back to the equation:

+(-3x+3)



We get rid of parentheses

x/()+(-9x+21)/()-3x+3=0

We multiply all the terms by the denominator


x+(-9x+21)-3x*()+3*()=0

We add all the numbers together, and all the variables

x+(-9x+21)-3x*()=0

We get rid of parentheses

x-9x-3x*()+21=0

We add all the numbers together, and all the variables

-8x-3x*()+21=0

We move all terms containing x to the left, all other terms to the right

-8x-3x*()=-21

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