3(4a-1)11a=7-3

Solution for 3(4a-1)11a=7-3 equation:

3(4a-1)11a=7-3

We move all terms to the left:

3(4a-1)11a-(7-3)=0

We add all the numbers together, and all the variables

3(4a-1)11a-4=0

We multiply parentheses

132a^2-33a-4=0

a = 132; b = -33; c = -4;
Δ = b2-4ac
Δ = -332-4·132·(-4)
Δ = 3201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-\sqrt{3201}}{2*132}=\frac{33-\sqrt{3201}}{264}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+\sqrt{3201}}{2*132}=\frac{33+\sqrt{3201}}{264}
$