(3-w)+1=(2w-4)+w

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Solution for (3-w)+1=(2w-4)+w equation: 



(3-w)+1=(2w-4)+w

We move all terms to the left:

(3-w)+1-((2w-4)+w)=0

We add all the numbers together, and all the variables

(-1w+3)-((2w-4)+w)+1=0

We get rid of parentheses

-1w-((2w-4)+w)+3+1=0



We calculate terms in parentheses: -((2w-4)+w), so:

(2w-4)+w

We add all the numbers together, and all the variables

w+(2w-4)

We get rid of parentheses

w+2w-4

We add all the numbers together, and all the variables

3w-4

Back to the equation:

-(3w-4)



We add all the numbers together, and all the variables

-1w-(3w-4)+4=0

We get rid of parentheses

-1w-3w+4+4=0

We add all the numbers together, and all the variables

-4w+8=0

We move all terms containing w to the left, all other terms to the right

-4w=-8

w=-8/-4

w=+2

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