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(x+6)+2*1/2x=24
We move all terms to the left:
(x+6)+2*1/2x-(24)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
x+2*1/2x+6-24=0
We multiply all the terms by the denominator
x*2x+6*2x-24*2x+2*1=0
We add all the numbers together, and all the variables
x*2x+6*2x-24*2x+2=0
Wy multiply elements
2x^2+12x-48x+2=0
We add all the numbers together, and all the variables
2x^2-36x+2=0
a = 2; b = -36; c = +2;
Δ = b2-4ac
Δ = -362-4·2·2
Δ = 1280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1280}=\sqrt{256*5}=\sqrt{256}*\sqrt{5}=16\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-16\sqrt{5}}{2*2}=\frac{36-16\sqrt{5}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+16\sqrt{5}}{2*2}=\frac{36+16\sqrt{5}}{4} $
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