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2x+12+1/2x+1/2x=24
We move all terms to the left:
2x+12+1/2x+1/2x-(24)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
2x+1/2x+1/2x-12=0
We multiply all the terms by the denominator
2x*2x-12*2x+1+1=0
We add all the numbers together, and all the variables
2x*2x-12*2x+2=0
Wy multiply elements
4x^2-24x+2=0
a = 4; b = -24; c = +2;
Δ = b2-4ac
Δ = -242-4·4·2
Δ = 544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{544}=\sqrt{16*34}=\sqrt{16}*\sqrt{34}=4\sqrt{34}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{34}}{2*4}=\frac{24-4\sqrt{34}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{34}}{2*4}=\frac{24+4\sqrt{34}}{8} $
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