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(x+6)(2x+5)+19=0
We multiply parentheses ..
(+2x^2+5x+12x+30)+19=0
We get rid of parentheses
2x^2+5x+12x+30+19=0
We add all the numbers together, and all the variables
2x^2+17x+49=0
a = 2; b = 17; c = +49;
Δ = b2-4ac
Δ = 172-4·2·49
Δ = -103
Delta is less than zero, so there is no solution for the equation
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