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1/x+x=140
We move all terms to the left:
1/x+x-(140)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
x+1/x-140=0
We multiply all the terms by the denominator
x*x-140*x+1=0
We add all the numbers together, and all the variables
-140x+x*x+1=0
Wy multiply elements
x^2-140x+1=0
a = 1; b = -140; c = +1;
Δ = b2-4ac
Δ = -1402-4·1·1
Δ = 19596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{19596}=\sqrt{4*4899}=\sqrt{4}*\sqrt{4899}=2\sqrt{4899}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-140)-2\sqrt{4899}}{2*1}=\frac{140-2\sqrt{4899}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-140)+2\sqrt{4899}}{2*1}=\frac{140+2\sqrt{4899}}{2} $
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