3(m-15)+20=m+100

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Solution for 3(m-15)+20=m+100 equation: 



3(m-15)+20=m+100

We move all terms to the left:

3(m-15)+20-(m+100)=0

We multiply parentheses

3m-(m+100)-45+20=0

We get rid of parentheses

3m-m-100-45+20=0

We add all the numbers together, and all the variables

2m-125=0

We move all terms containing m to the left, all other terms to the right

2m=125

m=125/2

m=62+1/2

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